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Solve the following : Show that of all rectangles inscribed in a given circle, the square has the maximum area. - Mathematics and Statistics

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प्रश्न

Solve the following : Show that of all rectangles inscribed in a given circle, the square has the maximum area.

योग
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उत्तर


Let ABCD be a rectangle inscribed in a circle of radius r. Let AB = x and BC = y.
Then x2 + y = 4r2                     … (1)
Area of rectangle = xy
= `xsqrt(4r^2 - x^2)`                 ...[By (1)]
Let f(x) = x2(4t2 – x2)
= 4r2x2 – x4

∴ f'(x) = `d/dx(4r^2x^2 - x^4)`

= 4r2 x 2x – 4x3
= 8r2x – 4x3
and
f"(x) = `d/dx(8r^2x - 4x^3)`

= 8r2 x 1 – 4 x 3x2
= 8r2 – 12x2
For maximum area, f'(x) = 0
∴ 8r2x – 4x3 = 0
∴ 4x3 = 8r2x
∴ x2 = 2r2                            ...[∵ x ≠ 0]
∴ x = `sqrt(2)r`                           ...[∵ x > 0]
and
`f"(sqrt(2r)) = 8r^2 – 12(sqrt(2r))`
= – 16r2 <  0
∴ f(x) is maximum when x = `sqrt(2)r` 
If x = `sqrt(2)r`, then from (1),
`(sqrt(2r))^2 + y^2` = 4r2
∴ y2 = 4r2 – 2r2 = 2r2
∴ y = `sqrt(2)r`                           ...[∵ y > 0]
∴ x = y
∴ rectangle is a square.
Hence, amongst all rectangles inscribed in a circle, the square has maximum area.

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अध्याय 2: Applications of Derivatives - Miscellaneous Exercise 2 [पृष्ठ ९३]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 2 Applications of Derivatives
Miscellaneous Exercise 2 | Q 13 | पृष्ठ ९३

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