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The maximum value of sin x . cos x is ______. - Mathematics

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प्रश्न

The maximum value of sin x . cos x is ______.

विकल्प

  • `1/4`

  • `1/2`

  • `sqrt(2)`

  • `2sqrt(2)`

MCQ
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उत्तर

The maximum value of sin x . cos x is `1/2`.

Explanation:

We have f(x) = sin x cos x

⇒ f(x) = `1/2 * 2 sin x cos x`

= `1/2 sin 2x`

f'(x) = `1/2 * 2 cos 2x`

⇒ f'(x) = cos 2x

Now for local maxima and local minima f'(x) = 0

∴ cos 2x = 0

2x = `("n" + 1) pi/2`, n ∈ I

⇒ x = `(2"n" + 1) pi/4`

∴ x = `pi/4, (3pi)/4` .....

f"(x) = – 2 sin 2x

`"f''"(x)_(x = pi/4)` = `-2 sin 2 * pi/4`

= `- 2 sin  pi/2`

= – 2 < 0 maxima

`"f''"(x)_(x = (3pi)/4) = - 2 sin 2 * (3pi)/4`

= `-2 sin  (3pi)/4`

= 2 > 0 minima

So f(x) is maximum at x = `pi/4`

∴ Maximum value of f(x) = `sin  pi/4 * cos  pi/4`

= `1/sqrt(2) * 1/sqrt(2)`

= `1/sqrt(2)`.

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अध्याय 6: Application Of Derivatives - Exercise [पृष्ठ १४१]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
अध्याय 6 Application Of Derivatives
Exercise | Q 55 | पृष्ठ १४१

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