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Find the Sum of All Those Integers Between 100 and 800 Each of Which on Division by 16 Leaves the Remainder 7. - Mathematics

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प्रश्न

Find the sum of all those integers between 100 and 800 each of which on division by 16 leaves the remainder 7.

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उत्तर

The sum of all those integers between 100 and 800 each of which on division by 16 leaves the remainder 7 are:
103, 119...791
Here, we have:
a = 103
d = 16

\[a_n = 791\]

\[\text { We know }: \]

\[ a_n = a + (n - 1)d\]

\[ \Rightarrow 791 = 103 + (n - 1) \times 16\]

\[ \Rightarrow 688 = 16n - 16\]

\[ \Rightarrow 704 = 16n\]

\[ \Rightarrow 44 = n\]

\[\text { Also }, S_n = \frac{n}{2}[2a + (n - 1)d]\]

\[ \Rightarrow S_{44} = \frac{44}{2}[2 \times 103 + (44 - 1) \times 16]\]

\[ \Rightarrow S_{44} = 22 [206 + 688]\]

\[ \Rightarrow S_{44} = 22 \times 894 = 19668\]

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अध्याय 19: Arithmetic Progression - Exercise 19.4 [पृष्ठ ३१]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 19 Arithmetic Progression
Exercise 19.4 | Q 13 | पृष्ठ ३१

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