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Evaluate: limx→0sin2x+3x2x+tan3x - Mathematics

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प्रश्न

Evaluate: `lim_(x -> 0) (sin 2x + 3x)/(2x + tan 3x)`

योग
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उत्तर

Given that `lim_(x -> 0) (sin 2x + 3x)/(2x + tan 3x)`

= `lim_(x -> 0) (((sin 2x + 3x)/(2x)) xx 2x)/(((2x + tan 3x)/(3x)) xx 3x)`

= `lim_(x -> 0)  (((sin 2x)/(2x) + (3x)/(2x)) xx 2x)/(((2x)/(3x) + (tan 3x)/(3x)) xx 3x)`

= `((lim_(2x -> 0)  (sin 2x)/(2x) + 3/2))/([2/3 + lim_(3x -> 0)  (tan 3x)/(3x)]) xx 2/3`   .....`[because  lim_(x -> 0)  sinx/x = 1]`

= `((1 + 3/2)/(2/3 + 1)) xx 2/3`  .....`[because  lim_(x -> 0)  tanx/x = 1]`

= `(5/2)/(5/3) xx 2/3`

= `3/2 xx 2/3`

= 1

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अध्याय 13: Limits and Derivatives - Exercise [पृष्ठ २४०]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
अध्याय 13 Limits and Derivatives
Exercise | Q 23 | पृष्ठ २४०

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