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Evaluate limx→π2(secx-tanx)

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प्रश्न

Evaluate `lim_(x -> pi/2) (secx - tanx)`

योग
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उत्तर

Put `y = pi/2 - x`.

Then y → 0 as x → `pi/2`.

Thereofre `lim_(x -> pi/2) (secx - tanx)`

= `lim_(y -> 0) [sec(pi/2 - y) - tan(pi/2 - y)]`

= `lim_(y -> 0) 1/siny = cosy/siny`

= `lim_(y -> 0) (1 - cosy)/siny`

= `lim_(y -> 0) (2sin^2  y/2)/(2sin  y/2 cos  y/2)`

Since, `sin^2  y/2 = (1 - cosy)/2`

sin y = `2sin  y/2 cos  y/2`

= `lim_(y/2 _> 0) tan  y/2` = 0

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अध्याय 13: Limits and Derivatives - Solved Examples [पृष्ठ २२८]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 11
अध्याय 13 Limits and Derivatives
Solved Examples | Q 4 | पृष्ठ २२८

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