हिंदी

Find the derivative of f(x) = sinx, by first principle.

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प्रश्न

Find the derivative of f(x) = `sqrt(sinx)`, by first principle.

योग
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उत्तर

By definition,

f'(x) = `lim_(h -> 0) (f(x + h) - f(x))/h`

= `lim_(h -> 0) (sqrt(sin (x + h)) - sqrt(sin x))/h`

= `lim_(h -> 0) ((sqrt(sin(x + h)) - sqrt(sinx))(sqrt(sin(x + h)) + sqrt(sinx)))/(h(sqrt(sin(x + h)) + sqrt(sinx))`

= `lim_(h -> 0) (sin(x + h) - sinx)/(h(sqrt(sin(x + h)) + sqrt(sinx))`

= `lim_(h -> 0) (2 cos  (2x + h)/2 sin  h/2)/(2 * h/2 (sqrt(sin(x + h)) + sqrt(sinx))`

= `cosx/(2sqrt(sinx))`

= `1/2 cot x sqrt(sinx)`

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अध्याय 13: Limits and Derivatives - Solved Examples [पृष्ठ २३५]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
अध्याय 13 Limits and Derivatives
Solved Examples | Q 20 | पृष्ठ २३५

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