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Evaluate the following limit. limx→0sinax+bxax+sinbxa,b,a+b≠0 - Mathematics

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प्रश्न

Evaluate the following limit.

`lim_(x -> 0) (sin ax + bx)/(ax + sin bx) a, b, a+ b != 0`

योग
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उत्तर

`lim_(x → 0)(sinax + bx)/(ax + sinbx)`

Dividing numerator and denominator by x

= `lim_(x → 0)((sin ax/x + b)/(a + sin bx/x))`

= `lim_(x → 0)(((sinax)/ax) a + b)/(a + ((sinbx)/bx) b)`

= `(1. a + b)/(a + 1.b)`

= `(a + b)/(a + b)`

= 1, a + b ≠ 0

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 13: Limits and Derivatives - Exercise 13.1 [पृष्ठ ३०२]

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एनसीईआरटी Mathematics [English] Class 11
अध्याय 13 Limits and Derivatives
Exercise 13.1 | Q 20 | पृष्ठ ३०२

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