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Evaluate limx→0tanx-sinxsin3x

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प्रश्न

Evaluate `lim_(x -> 0) (tanx - sinx)/(sin^3x)`

योग
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उत्तर

We have `lim_(x -> 0) (tanx - sinx)/(sin^3x)`

= `lim_(x -> 0) (sinx  1/cosx - 1)/(sin^3x)`

= `lim_(x -> 0) (1 - cosx)/(cosx sin^2x)`

= `lim_( -> 0) (2sin^2  x/2)/(cosx  4sin^2  x/2 * cos^2  x/2)`

= `1/2`.

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अध्याय 13: Limits and Derivatives - Solved Examples [पृष्ठ २३३]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 11
अध्याय 13 Limits and Derivatives
Solved Examples | Q 15 | पृष्ठ २३३

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