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Evaluate the following limit : limx→π6[2sin2x+sinx-12sin2x-3sinx+1] - Mathematics and Statistics

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प्रश्न

Evaluate the following limit :

`lim_(x -> pi/6) [(2sin^2x + sinx - 1)/(2sin^2x - 3sinx + 1)]`

योग
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उत्तर

`lim_(x -> pi/6) (2sin^2x + sinx - 1)/(2sin^2x - 3sinx + 1)`

= `lim_(x -> pi/6) ((2sinx - 1)(sin x + 1))/((2sin x - 1)(sin x - 1))`

= `lim_(x -> pi/6) (sinx + 1)/(sin x - 1)   ...[(because x -> pi/6","  x ≠ pi/6),(therefore sin x ≠ sin  pi/6 = 1/2),(therefore 2 sin x - 1 ≠ 0)]`

= `(lim_(x -> pi/6) (sin x + 1))/(lim_(x -> pi/6) (sin x - 1))`

= `(sin  pi/6 + 1)/(sin  pi/6 - 1)`

= `(1/2 + 1)/(1/2 - 1)`

= `(1 + 2)/(1 - 2)`

= – 3

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अध्याय 7: Limits - Exercise 7.4 [पृष्ठ १४८]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 11 Maharashtra State Board
अध्याय 7 Limits
Exercise 7.4 | Q III. (4) | पृष्ठ १४८

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