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Equation of the Diameter of the Circle X2 + Y2 − 2x + 4y = 0 Which Passes Through the Origin is - Mathematics

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प्रश्न

Equation of the diameter of the circle x2 + y2 − 2x + 4y = 0 which passes through the origin is

विकल्प

  • x + 2y = 0

  • x − 2y = 0

  • 2x + y = 0

  • 2x − y = 0Let the diameter of the circle be y = mx.
    Since the diameter of the circle passes through its centre, (1, −2) satisfies the equation of the diameter.

MCQ
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उत्तर

2x + y = 0

Let the diameter of the circle be y = mx.
Since the diameter of the circle passes through its centre, (1, −2) satisfies the equation of the diameter.

∴ \[m =  - 2\]

Substituting the value of m in the equation of diameter:

\[y = - 2x\] 
\[\Rightarrow 2x + y = 0\]
Hence, the required equation of the diameter is
\[2x + y = 0\].
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Advanced Concept of Circle - Standard Equation of a Circle
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अध्याय 24: The circle - Exercise 24.6 [पृष्ठ ४०]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 24 The circle
Exercise 24.6 | Q 23 | पृष्ठ ४०

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