Advertisements
Advertisements
प्रश्न
Earth also moves in circular orbit around sun once every year with on orbital radius of 1.5 × 1011 m. What is the acceleration of earth (or any object on the surface of the earth) towards the centre of the sun? How does this acceleration compare with g = 9.8 m/s2?
Advertisements
उत्तर
The orbital radius of the earth around the sun (R) = 1.5 × 1011 m
Time period = 1 yr = 365 day
= 365 × 24 × 60 × 60 s
= 3.15 ×107 s
Centripetal acceleration `(a_c) = Rω^2 = (5pi^2R)/T^2`
= `(4 xx (22/7)^2 xx 1.5 xx 10^11)/(3.15 xx 10^7)^2`
= `5.97 xx 10^-3` m/s2
∴ `a_c/g = (5.97 xx 10^-3)/9.8 = 1/1642`
APPEARS IN
संबंधित प्रश्न
For a particle performing uniform circular motion `vecv=vecomegaxxvecr`obtain an expression for linear acceleration of the particle performing non-uniform circular motion.
The motion of the moon around the earth in a circular path is an accelerated motion.
Name the force required for uniform circular motion. State its direction.
Define angular velocity.
Answer the following question.
Show that the centripetal force on a particle undergoing uniform circular motion is -mrω2.
Solve the following problem.
A projectile is thrown at an angle of 30° to the horizontal. What should be the range of initial velocity (u) so that its range will be between 40m and 50 m? Assume g = 10 m s-2.
Which one of the following is most likely not a case of uniform circular motion?
A particle is moving in uniform circular motion with speed 'V' and radius 'R'. The angular acceleration of the particle is ______.
A wheel is 0.25 m in radius. When it makes 15 revolutions per minute, its linear speed at the point on circumference is ____________.
A mass 'm' is tied to one end of a spring and whirled in a horizontal circle with constant angular velocity. The elongation in the spring is 1 cm. If the angular speed is doubled, the elongation in the spring is 6 cm. The original length of the spring is ______.
Statement A: Uniform circular motion is a case of accelerated motion
Statement B: In the third equation of motion we do not have the term time
A simple pendulum of length l has maximum angular displacement θ. The maximum kinetic energy of the bob of mass m is ______.
(g = acceleration due to gravity)
A particle is performing a uniform circular motion along a circle of radius R. In half the period of revolution, its displacement and distance covered are respectively.
A wheel is Subjected to uniform angular acceleration about its axis. Initially. its angular velocity is zero. In the first 2 s, it rotates through an angle θ1, in the next 2 s, it rotates through an angle θ2. The ratio of `theta_2/theta_1` is ______.
Explain the meaning of uniform circular motion.
What is the direction of the velocity of an object at any point during uniform circular motion?
In uniform circular motion, although the speed is constant, why does acceleration occur?
By applying Kepler's third law to the formula for centripetal force, Newton concluded that the force acting on a planet is:
A particle moving with uniform speed in a circular path maintains ______.
