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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान कक्षा ११

Dry ice is ______.

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प्रश्न

Dry ice is ______.

विकल्प

  • Solid NH3

  • Solid SO2

  • Solid CO2

  • Solid N2

MCQ
रिक्त स्थान भरें
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उत्तर

Dry ice is solid CO2.

Explanation:

Solid CO2 is referred to as dry ice because it is used in laboratories to create an ice bath for organic reactions. It is made by rapidly cooling high-pressure CO2 gas.

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अध्याय 11: The p-block Elements - Multiple Choice Questions (Type - I) [पृष्ठ १३६]

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एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 11
अध्याय 11 The p-block Elements
Multiple Choice Questions (Type - I) | Q 14 | पृष्ठ १३६

संबंधित प्रश्न

If B–Cl bond has a dipole moment, explain why BCl3 molecule has zero dipole moment.


How would you explain the lower atomic radius of Ga as compared to Al?


What do you understand by inert pair effect?


The geometry of a complex species can be understood from the knowledge of type of hybridisation of orbitals of central atom. The hybridisation of orbitals of central atom in [Be(OH)4]– and the geometry of the complex are respectively.


A compound X, of boron reacts with NH3 on heating to give another compound Y which is called inorganic benzene. The compound X can be prepared by treating BF3 with Lithium aluminium hydride. The compounds X and Y are represented by the formulas.


When BCl3 is treated with water, it hydrolyses and forms [B[OH]4]– only whereas AlCl3 in acidified aqueous solution forms [Al(H2O)6]3+ ion. Explain what is the hybridisation of boron and aluminium in these species?


Explain the following:

Boron does not exist as B3+ ion.


Explain the following:

Electron gain enthalpy of chlorine is more negative as compared to fluorine.


Identify the compounds A, X and Z in the following reactions:

\[\ce{A + 2HCl + 5H2O -> 2NaCl + X}\]


Identify the compounds A, X and Z in the following reactions:

\[\ce{X ->[Δ][370 K] HBO2 ->[Δ][> 370 K] Z}\]


Match the species given in Column I with the properties mentioned in Column II.

Column I Column II
(i) \[\ce{BF^{-}4}\] (a) Oxidation state of central atom is +4
(ii) AICI3 (b) Strong oxidising agent
(iii) SnO (c) Lewis acid
(iv) PbO2 (d) Can be further oxidised
  (e) Tetrahedral shape

Match the species given in Column I with properties given in Column II.

Column I Column II
(i) Diborane (a) Used as a flux for soldering metals
(ii) Galluim (b) Crystalline form of silica
(iii) Borax (c) Banana bonds
(iv) Aluminosilicate (d) Low melting, high boiling, useful for measuring high temperatures
(v) Quartz (e) Used as catalyst in petrochemical industries

Describe the general trends in the following properties of the elements in Groups 13 and 14.

Metallic character


Three pairs of compounds are given below. Identify that compound in each of the pairs which has group 13 element in more stable oxidation state. Give reason for your choice. State the nature of bonding also.

TlCl3, TlCl


BCl3 exists as monomer whereas AlCl3 is dimerised through halogen bridging. Give reason. Explain the structure of the dimer of AlCl3 also.


Boron compounds behave as Lewis acids because of their ______.


Taking stability as the factor, which one of the following represents the correct relationship?


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