Advertisements
Advertisements
प्रश्न
Draw the structure of the semicarbazone of ethanal.
Advertisements
उत्तर
\[\begin{array}{cc}
\ce{H3C}\phantom{.........................}\ce{O}\phantom{..................}\ce{H}\phantom{..............}\ce{O}\phantom{.............}\\
\phantom{..}\backslash\phantom{........................}||\phantom{...................}|\phantom{...............}||\phantom{...........}\\
\ce{\underset{Ethanal}{C = O} + H2N - NH - C - NH2 -> \underset{Semicarbazone}{CH3 - C = N - NH - C - NH2}}\\
/\phantom{.....................................................................}\\
\ce{H}\phantom{........................................................................}\\
\end{array}\]
APPEARS IN
संबंधित प्रश्न
Write the structures of the main products when acetone (CH3 − CO − CH3) reacts with the following reagent :
H2N − NHCONH2/H+
Predict the product of the following reaction:
\[\begin{array}{cc}
\phantom{..............}\ce{O}\\
\phantom{..............}||\\
\ce{R - CH = CH - CHO + NH2 - C - NH - NH2 ->[H+]}\end{array}\]
Acetone, Acetaldehyde, Benzaldehyde, Acetophenone – reactivity towards addition of HCN.
How will you convert benzoic acid to m-bromobenzoic acid?
Benzaldehyde can be obtained from benzal chloride. Write reactions for obtaining benzalchloride and then benzaldehyde from it.
The most stable reagent for the conversion of R – CH2OH → RCHO is

The product "P" in the above reaction is:
Draw structure of the following derivative.
Acetaldehydedimethylacetal
Why dissociation of HCN is suppressed by the addition of HCL?
Draw the structure of the following derivative.
Acetaldehydedimethylacetal
