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प्रश्न
Give reasons for the following:
Ammonolysis of alkyl halides is not a good method to prepare pure primary amines.
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उत्तर
Ammonolysis of alkyl halides leads to the formation of a mixture of primary, secondary, tertiary amines and quaternary salts. It is because every time a nucleophilic substitution reaction takes place, an amine acts as a nucleophile and forms a primary amine, which further reacts and forms a secondary amine, which again reacts with the alkyl halide to form a tertiary amine and further leads to the formation of a quaternary salt. Thus, the ammonolysis reaction forms a mixture of all four compounds, and it will be difficult to get the pure amine.
\[\ce{\underset{Alkyl halide}{R-X} ->[NH3][-HX] R - NH2 ->[R-X][-HX] R2NH ->[R-X][-HX] R3N ->[R-X] R4\overset{+}{N}X^-}\]
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संबंधित प्रश्न
How do you convert the following: C6H5CONH2 to C6H5NH2
Accomplish the following conversion:
Nitrobenzene to benzoic acid
Give the structures of A, B and C in the following reaction:
\[\ce{CH3COOH ->[NH3][\Delta] A ->[NaOBr] B ->[NaNO2/HCl] C}\]
Answer in one sentence.
Predict the product of the following reaction.
\[\ce{Nitrobenzene ->[Sn/conc.HCl]?}\]
Why cannot aniline be prepared by Gabriel phthalimide synthesis?
Acetamide on reduction using Na/C2H5OH gives ____________.
Write following conversions:
acetanilide `->` p-nitroaniline
Match the reactions given in Column I with the statements given in Column II.
| Column I | Column II | ||
| (i) | Ammonolysis | (a) | Amine with lesser number of carbon atoms |
| (ii) | Gabriel phthalimide synthesis | (b) | Detection test for primary amines. |
| (iii) | Hoffmann Bromamide reaction | (c) | Reaction of phthalimide with \[\ce{KOH}\] and \[\ce{R-X}\] |
| (iv) | Carbylamine reaction | (d) | Reaction of alkylhalides with \[\ce{NH3}\] |
Acetamide and ethyl amide can be distinguished by reacting with.
Assertion: Amimonolysis of alkyl halides involves the reaction between alkyl halides and alcoholic ammonia.
Reason: Ammonolysis of alkyl halides produces secondary amines only.
