Question

cot θ + tan θ = cosec θ × sec θ, हे सिद्ध करण्यासाठी खालील कृती पूर्ण करा.

कृती:

डावी बाजू = `square`

= `square/sintheta + sintheta/costheta`

= `(cos^2theta + sin^2theta)/square`

= `1/(sintheta*costheta)`     ......`[cos^2theta + sin^2theta = square]`

= `1/sintheta xx 1/square`

= `square`

= उजवी बाजू

Answer 1

डावी बाजू = cot θ + tan θ

= `bb(costheta)/sintheta + sintheta/costheta`

= `(cos^2theta + sin^2theta)/bb((sintheta*costheta))`

= `1/(sintheta*costheta)`     ......[cos²θ + sin²θ = 1]

= `1/sintheta xx 1/bb(costheta)`

= cosecθ × secθ

= उजवी बाजू