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∫ Cos X √ 4 − Sin 2 X D X - Mathematics

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प्रश्न

\[\int\frac{\cos x}{\sqrt{4 - \sin^2 x}} dx\]
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उत्तर

 `  ∫ cos  x / \sqrt{4-sin^2 x}`
\[\text{ let }\sin x = t\]
\[ \Rightarrow \text{ cos x dx }= dt\]
Now,  `  ∫ cos  x / \sqrt{4-sin^2 x}`
\[ = \int\frac{dt}{\sqrt{4 - t^2}}\]
\[ = \int\frac{dt}{\sqrt{2^2 - t^2}}\]
\[ = \sin^{- 1} \left( \frac{t}{2} \right) + C\]
\[ = \sin^{- 1} \left( \frac{\sin x}{2} \right) + C\]

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 19: Indefinite Integrals - Exercise 19.18 [पृष्ठ ९९]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 19 Indefinite Integrals
Exercise 19.18 | Q 12 | पृष्ठ ९९

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