हिंदी

Construct a Frequency Polygon Without Using a Histogram for the Following Frequency Distribution : Class Interval 1-10 11-20 21-30 31-40 41-50 Frequency 8 12 10 16 6

Advertisements
Advertisements

प्रश्न

Construct a frequency polygon without using a histogram for the following frequency distribution :

Class Interval  1-10 11-20 21-30 31-40 41-50
Frequency 8 12 10 16 6
योग
Advertisements

उत्तर

Steps : 

1. Make the class intervals continuous by subtracting 0.5 from the lower limit of each class and add 0.5 to the upper limit of each class .

2. Find class mark by calculating the average of the class interval.

3. On the x-axis , take 1 cm as 5 units and plot class interval.

4. On the y-axis , take 1 cm as 5 units and plot frequency.

5. Plot the points on the graph. (5.5,8),(15.5,12),(25.5,10),(35.5,16),(45.5,6).

6. Mark two more midpoints of zero frequency on x-axis at the start and at the end.

7. Now connect the points using straight lines.

Class Interval Class Mark Frequency
0.5-10.5 = `(0.5+10.5)/2 = 5.5` 8
10.5-20.5 = `(10.5+20.5)/2 = 15.5` 12
20.5-30.5 = `(20.5 + 30.5)/2 = 25.5` 10
30.5-40.5 = `(30.5 + 40.5)/2 = 35.5` 16
40.5-50.5 = `(40.5 + 50.5)/2 = 45.5` 6

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 23: Graphical Representations - Exercise

APPEARS IN

फ्रैंक Mathematics Part 2 [English] Class 10 ICSE
अध्याय 23 Graphical Representations
Exercise | Q 3.03

संबंधित प्रश्न

The weekly wages (in Rs) of 30 workers in a factory are.

830, 835, 890, 810, 835, 836, 869, 845, 898, 890, 820, 860, 832, 833, 855, 845, 804, 808, 812, 840, 885, 835, 835, 836, 878, 840, 868, 890, 806, 840

Using tally marks make a frequency table with intervals as 800 − 810, 810 − 820 and so on.


Given below is the frequency distribution of the heights of 50 students of a class:

Class interval: 140−145 145−150 150−155 155−160 160−165
Frequency: 8 12 18 10 5

Draw a histogram representing the above data.


Draw a histogram of the following data:

Class interval: 10−15 15−20 20−25 25−30 30−35 34−40
Frequency: 30 98 80 58 29 50

Distribution of height in cm of 100 people is given below:

Class interval (cm) Frequency
145 - 155 3
155 - 165 35
165 - 175 25
175 - 185 15
185 - 195 20
195 - 205 2

Draw a histogram to represent the above data.


The total area of the histogram is _________ to the total frequency of the given data


Histogram is a graphical representation of ___________ data


Construct a histogram from the following distribution of total marks of 40 students in a class.

Marks 90 − 110 110 − 130 130 − 150 150 − 170 170 − 190 190 − 210
No. of Students 9 5 10 7 4 6

Histogram shows the number of people owning the different number of books. Answer the question based on it.


The total number of people surveyed is ______.


In a histogram, class intervals and frequencies are taken along ______ axis and ______ axis.


The table given below shows the runs scored by a cricket team during the overs of a match.

Overs Runs scored
20 – 30 37
30 – 40 45
40 – 50 40
50 – 60 60
60 – 70 51
70 – 80 35

Use graph sheet for this question.

Take 2 cm = 10 overs along one axis and 2 cm = 10 runs along the other axis.

  1. Draw a histogram representing the above distribution.
  2. Estimate the modal runs scored.

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×