Advertisements
Advertisements
प्रश्न
Construct a frequency polygon without using a histogram for the following frequency distribution :
| Class Interval | 10-20 | 20-40 | 40-60 | 60-80 | 80-100 |
| Frequency | 9 | 17 | 15 | 20 | 14 |
Advertisements
उत्तर
Steps :
1. Find class mark by calculating the average of the class interval.
2. On the x-axis , take 1 cm as 5 units and plot class interval.
3. On the y-axis , take 1 cm as 5 units and plot frequency.
4. plot the points on the graph. (15,9),(30,17),(50,15),(70,20),(90,14).
5. Mark two more midpoints of zero frequency on x-axis at the start and at the end .
6. Now connect the points using staright lines.
| Class Interval | Class mark | Frequency |
| 10-20 | `= (10+20)/2 = 15` | 9 |
| 20-40 | `= (20+40)/2 = 30` | 17 |
| 40-60 | `= (40+60)/2 = 50` | 15 |
| 60-80 | `= (60 + 80)/2 = 70` | 20 |
| 80-100 | `= (80 + 100)/2 = 90` | 14 |
APPEARS IN
संबंधित प्रश्न
The shoppers who come to a departmental store are marked as: man (M), woman (W), boy (B) or girl (G). The following list gives the shoppers who came during the first hour in the morning
W W W G B W W M G G M M W W W W G B M W B G G M W W M M W W W M W B W G M W W W W G W M M W W M W G W M G W M M B G G W
Make a frequency distribution table using tally marks. Draw a bar graph to illustrate it.
The number of hours for which students of a particular class watched television during holidays is shown through the given graph.
Answer the following
1) For how many hours did the maximum number of students watch TV?
2) How many students watched TV for less than 4 hours?
3) How many students spent more than 5 hours in watching TV?
The table below shows the yield of jowar per acre. Show the data by histogram.
| Yield per acre (quintal) | 2 - 3 | 4 - 5 | 6 - 7 | 8 - 9 | 10 - 11 |
| No. of farmers | 30 | 50 | 55 | 40 | 20 |
Construct a histogram for the following data:
| Monthly school fee (in Rs): | 30−60 | 60−90 | 90−120 | 120−150 | 150−180 | 180−210 | 210−240 |
| Number of schools: | 5 | 12 | 14 | 18 | 10 | 9 | 4 |
Draw histogram and hence the frequency polygon for the following frequency distribution:
| Rainfall (in cm) | No. of years |
| 20-25 | 2 |
| 25-30 | 5 |
| 30-35 | 8 |
| 35-40 | 12 |
| 40-45 | 10 |
| 45-50 | 7 |
Distribution of height in cm of 100 people is given below:
| Class interval (cm) | Frequency |
| 145 - 155 | 3 |
| 155 - 165 | 35 |
| 165 - 175 | 25 |
| 175 - 185 | 15 |
| 185 - 195 | 20 |
| 195 - 205 | 2 |
Draw a histogram to represent the above data.
The time taken, in seconds, to solve a problem for each of 25 persons is as follows:
| 16 | 20 | 26 | 27 | 28 |
| 30 | 33 | 37 | 38 | 40 |
| 42 | 43 | 46 | 46 | 47 |
| 48 | 49 | 50 | 53 | 58 |
| 59 | 60 | 64 | 52 | 20 |
(i) Construct a frequency distribution for these data using a class interval of 10 seconds.
(ii) In a school the weekly pocket money of 50 students is as follow's:
| Weekly pocket money (₹) | No. of student |
| 40 - 50 | 2 |
| 59 - 60 | 8 |
| 60 - 70 | 12 |
| 70 - 80 | 14 |
| 80 - 90 | 8 |
| 90 - 100 | 6 |
Draw a histogram and a frequency polygon on the same graph. Find mode from the graph.
Identify the following data can be represented in a histogram?
The wickets fallen from 1 over to 50th over in a one day cricket match
The top speeds of thirty different land animals have been organised into a frequency table. Draw a histogram for the given data.
| Maximum Speed (km/h) | Frequency |
| 10 – 20 | 5 |
| 20 – 30 | 5 |
| 30 – 40 | 10 |
| 40 – 50 | 8 |
| 50 – 60 | 0 |
| 60 – 70 | 2 |
Use graph paper for this question. Estimate the mode of the given distribution by plotting a histogram. [Take 2 cm = 10 marks along one axis and 2 cm = 5 students along the other axis]
| Daily wages (in ₹) | 30 - 40 | 40 - 50 | 50 - 60 | 60 - 70 | 70 - 80 |
| No. of Workers | 6 | 12 | 20 | 15 | 9 |
