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CDE is an equilateral triangle formed on a side CD of a square ABCD (Figure). Show that ∆ADE ≅ ∆BCE. - Mathematics

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प्रश्न

CDE is an equilateral triangle formed on a side CD of a square ABCD (Figure). Show that ∆ADE ≅ ∆BCE.

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उत्तर

Given in figure triangle CDE is an equilateral triangle formed on a side CD of a square ABCD.

To proof that ΔADE ≅ ∆BCE

Proof: In triangle ADE and triangle BCE,

DE = CE  ...[Side of an equilateral triangle]

∠ADE = ∠BCE

∠ADC = ∠BCD = 90° and ∠EDC = ∠ECD = 60°

∠ADE = 90° + 60° = 150° and ∠BCE = 90° + 60° = 150°

AD = BC  ...[Sides of a square]

∆ADE ≅ ∆BCE   ...[By SAS congruence rule]

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अध्याय 7: Triangles - Exercise 7.3 [पृष्ठ ६७]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 9
अध्याय 7 Triangles
Exercise 7.3 | Q 3. | पृष्ठ ६७

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