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In the following figure, D and E are points on side BC of a ∆ABC such that BD = CE and AD = AE. Show that ∆ABD ≅ ∆ACE.

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प्रश्न

In the following figure, D and E are points on side BC of a ∆ABC such that BD = CE and AD = AE. Show that ∆ABD ≅ ∆ACE.

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उत्तर

Given: D and E are the points on side BC of a ∆ABC such that BD = CE and AD = AE. 

To show: ∆ABD ≅ ∆ACE

Proof: We have, AD = AE  ...[Given]

⇒ ∠ADE = ∠AED  ...(i) [Since, angles opposite to equal sides are equal] 

We have, ∠ADB + ∠ADE = 180°  ...[Linear pair axiom]

⇒ ∠ADB = 180° – ∠ADE

= 180° – ∠AED  ...[From equation (i)]

In ∆ABD and ∆ACE,

∠ADB = ∠AEC  ...[∵ ∠AEC + ∠AED = 180°, linear pair axiom]

BD = CE   ...[Given]

And AD = AE   ...[Given]

∴ ∆ABD ≅ ∆ACE  ...[By SAS congruence rule]

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अध्याय 7: Triangles - Exercise 7.3 [पृष्ठ ६७]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 9
अध्याय 7 Triangles
Exercise 7.3 | Q 2. | पृष्ठ ६७

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