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If the Bisectors of the Acute Angles of a Right Triangle Meet at O, Then the Angle at O Between the Two Bisectors is

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प्रश्न

If the bisectors of the acute angles of a right triangle meet at O, then the angle at Obetween the two bisectors is

विकल्प

  • 45°

  •  95°

  • 135°

  • 90°

MCQ
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उत्तर

In the given problem, bisectors of the acute angles of a right angled triangle meet at O. We need to find  ∠AOC.

Now, using the angle sum property of a triangle

In ΔABC

∠A + ∠B + ∠C = 180° 

90° + ∠A+ ∠C = 180°

        ∠A + ∠C = 90°   ..............(1)

Now, further multiplying each of the term by  1/2in (1)

`1/2 ∠A + 1/2 ∠C = 1/2 90°`

∠OAC + ∠ACO = 45°

Also, applying angle sum property of a triangle

In ΔAOC

∠OAC + ∠ACO + ∠AOC = 180°

                   45° + ∠AOC = 180°

                            ∠AOC = 180° - 45° 

                                      = 135°

Thus, ∠AOC = 135°

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अध्याय 11: Triangle and its Angles - Exercise 11.4 [पृष्ठ २९]

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आर.डी. शर्मा Mathematics [English] Class 9
अध्याय 11 Triangle and its Angles
Exercise 11.4 | Q 25 | पृष्ठ २९

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

In an isosceles triangle ABC, with AB = AC, the bisectors of ∠B and ∠C intersect each other at O. Join A to O. Show that:

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ABC is a triangle in which altitudes BE and CF to sides AC and AB are equal (see the given figure). Show that

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  2. AB = AC, i.e., ABC is an isosceles triangle.


In a ΔABC, if ∠A=l20° and AB = AC. Find ∠B and ∠C. 


In Figure 10.24, AB = AC and ∠ACD =105°, find ∠BAC. 

 


BD and CE are bisectors of ∠B and ∠C of an isosceles ΔABC with AB = AC. Prove that BD = CE. 


Which of the following statements are true (T) and which are false (F): 

The bisectors of two equal angles of a triangle are equal 


Fill the blank in the following so that the following statement is true. 

Angle opposite to equal sides of a triangle are ..... 


Fill the blank in the following so that the following statement is true. 

In an isosceles triangle ABC with AB = AC, if BD and CE are its altitudes, then BD is …… CE.


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In ΔABC, side AB is produced to D so that BD = BC. If ∠B = 60° and ∠A = 70°, prove that: (i) AD > CD (ii) AD > AC 


O is any point in the interior of ΔABC. Prove that
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Which of the following statements are true (T) and which are false (F)? 

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In the given figure, if AB ⊥ BC. then x =


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ABC is an isosceles triangle with AB = AC and D is a point on BC such that AD ⊥ BC (Figure). To prove that ∠BAD = ∠CAD, a student proceeded as follows:


In ∆ABD and ∆ACD,

AB = AC (Given)

∠B = ∠C (Because AB = AC)

and ∠ADB = ∠ADC

Therefore, ∆ABD ≅ ∆ACD (AAS)

So, ∠BAD = ∠CAD (CPCT)

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[Hint: Recall how ∠B = ∠C is proved when AB = AC].


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