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In the Given Figure, If Ab ⊥ Bc. Then X =

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प्रश्न

In the given figure, if AB ⊥ BC. then x =

विकल्प

  • 18

  • 22

  • 25

  • 32

MCQ
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उत्तर

In the given figure, AB ⊥ BC

We need to find the value of x.

Now, since AB and CD are straight lines intersecting at point O, using the property, “vertically opposite angles are equal”, we get,

∠BOC = ∠AOD

∠BOC = 32° 

Further, applying angle sum property of the triangle 

In ΔBOC 

∠BOC + ∠OBC + ∠BCO = 180° 

           32°  + 90°  + ∠BCO = 180° 

                          ∠BCO  = 180°  -122° 

                          ∠BCO = 58°     

Then, using the property, “an exterior angle of the triangle is equal to the sum of the two opposite interior angles”, we get,

In ΔEOC

∠BCO = ∠OEC +∠EOC  

58°  = (x + 14)°  + x

58°  = 2x + 14° 

2x = 58°  - 14° 

Further solving for x, we get,

2x = 44° 

`x = (44° )/2`

x = 22°  

Thus x = 22° 

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अध्याय 11: Triangle and its Angles - Exercise 11.4 [पृष्ठ २६]

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आर.डी. शर्मा Mathematics [English] Class 9
अध्याय 11 Triangle and its Angles
Exercise 11.4 | Q 16 | पृष्ठ २६

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