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ABC is an isosceles triangle in which altitudes BE and CF are drawn to equal sides AC and AB respectively (see the given figure). Show that these altitudes are equal. - Mathematics

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प्रश्न

ABC is an isosceles triangle in which altitudes BE and CF are drawn to equal sides AC and AB respectively (see the given figure). Show that these altitudes are equal.

योग
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उत्तर

△ABC is an isosceles triangle.

∴ AB = AC

∠ACB = ∠ABC         ...[Angles opposite to equal sides of a △ are equal]

∠BCE = ∠CBF

Now, in △BEC and △CFB

∠BCE = ∠CBF     ...[Proved above]

∠BEC = ∠CFB     ...[Each 90°]

BC = CB          ...[Common] 

∴ △BEC ≅ △CFB     ...[By AAS congruence]

So, BE = CF        ...[By Corresponding parts of congruent triangles]

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अध्याय 7: Triangles - Exercise 7.2 [पृष्ठ १२४]

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एनसीईआरटी Mathematics [English] Class 9
अध्याय 7 Triangles
Exercise 7.2 | Q 3 | पृष्ठ १२४

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