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प्रश्न
Boojho goes to the football ground to play football. The distance-time graph of his journey from his home to the ground is given in the figure.
- What does the graph between points B and C indicate about the motion of Boojho?
- Is the motion between 0 to 4 minutes uniform or non-uniform?
- What is his speed between 8 and 12 minutes of his journey?
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उत्तर
a. Graph between points B and C is a horizontal line which indicates that Boojho is at rest, i.e., his speed is zero.
b. Motion between 0 to 4 minutes is non-uniform as distance-time graph for this time interval is not a straight line.
c. Speed of Boojho between 8 and 12 minutes of his journey
= `((225 - 150) "m")/((12 - 8) "min")`
= `75/4`
= 18.75 m/min
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संबंधित प्रश्न
What can you say about the motion of an object if its speed-time graph is a straight line parallel to the time axis?
Show the shape of the distance-time graph for the motion in the following case:
A car moving with a constant speed.
What conclusion can you draw about the speed of a body from the following distance-time graph ?
A student draws a distance-time graph for a moving scooter and finds that a section of the graph is horizontal line parallel to the time axis. Which of the following conclusion is correct about this section of the graph?
What are the uses of the graphical study of motion?
The area under velocity time graph represents ______.
The slope of the distance-time curve is steeper/greater is the ______.
The slope of the distance-time graph indicates the speed.
Assertion: The slope of the distance-time graph of a body moving with high speed is steeper than the slope of the distance-time graph of a body with low velocity.
Reason: Slope of distance-time graph = speed of the body.
What do you infer if
- Distance – time graph is a straight line.
- The velocity-time graph is curved.
- Displacement time is zigzag.
