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प्रश्न
Answer the following question.
What is the unit of dipole moment?
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उत्तर
- Strength of a dipole is measured in terms of a quantity called the dipole moment.

- Let q be the magnitude of each charge and `2vec"l"` be the distance from the negative charge to the positive charge. Then, the product `"q"(2vec"l")` is called the dipole moment `vec"p"`.
- Dipole moment is defined as `vec"p"="q"(2vec"l")`
- A dipole moment is a vector whose magnitude is q (2l) and the direction is from the negative to the positive charge.
- The unit of dipole moment is coulomb-meter (C m) or debye (D).
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संबंधित प्रश्न
An electric dipole of dipole moment`vecp` consists of point charges +q and −q separated by a distance 2a apart. Deduce the expression for the electric field `vecE` due to the dipole at a distance x from the centre of the dipole on its axial line in terms of the dipole moment `vecp`. Hence show that in the limit x>> a, `vecE->2vecp"/"(4piepsilon_0x^3)`
An electric dipole of length 4 cm, when placed with its axis making an angle of 60° with a uniform electric field, experiences a torque of `4sqrt3`Nm. Calculate the potential energy of the dipole, if it has charge ±8 nC
A system has two charges qA = 2.5 × 10−7 C and qB = −2.5 × 10−7 C located at points A: (0, 0, −15 cm) and B: (0, 0, +15 cm), respectively. What are the total charge and electric dipole moment of the system?
An electric dipole of length 2 cm, when placed with its axis making an angle of 60° with a uniform electric field, experiences a torque of \[8\sqrt{3}\] Nm. Calculate the potential energy of the dipole, if it has a charge \[\pm\] 4 nC.
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A dipole is placed in an electric field as shown. In which direction will it move?

A dipole is placed in an electric field as shown. In which direction will it move?

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The electric potential V as a function of distance X is shown in the figure.
The graph of the magnitude of electric field intensity E as a function of X is ______.
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E = `(1/(4 pi epsilon_0)) p/((r^2 + l^2)^(3//2))`
Where the terms have their usual meaning.
