Advertisements
Advertisements
प्रश्न
An ideal gas is taken in a cyclic process as shown in the figure. Calculate
- work done by the gas
- work done on the gas
- Net work done in the process
Advertisements
उत्तर
a. Work done by the gas (along with AB)
W = P × ΔV = 600 × 3 = 1800 J
W = 1.8 kJ
b. Work is done on the gas (along with BC)
W = −P × ΔV = −400 × 3 = −1200 J
W = −1.2 kJ
c. Net work done in the process = Area under the curve AB
= Rectangle area + triangle area
= `("l" xx "b") + (1/2 xx "b" xx "h")`
= `(400 xx 3) + (1/2 xx 3 xx 200)`
= 1200 + 300
= 1500 J
W = 1.5 kJ
APPEARS IN
संबंधित प्रश्न
What is a thermodynamic process?
Explain the thermodynamics of the isochoric process.
The V-T diagram of an ideal gas which goes through a reversible cycle A→B→C→D is shown below. (Processes D→A and B→C are adiabatic)
The corresponding PV diagram for the process is (all figures are schematic)
Give an equation state for an isochoric process.
Explain the isobaric process and derive the work done in this process.
Draw the TP diagram (P-x axis, T-y axis), VT(T-x axis, V-y axis) diagram for
- Isochoric process
- Isothermal process
- Isobaric process
One mole of an ideal gas with `gamma` = 1.4 is adiabatically compressed so that its temperature rises from 27° C to 47° C. The change in the internal energy of the gas is (R = 8.3 J/mol.K) ____________.
An ideal gas is compressed to half its initial volume by means of several processes. Which of the process results in the maximum work done on the gas?
Which of the following processes is reversible?
When an inflated ballon is suddenly burst, why is the emerging air slightly cooled?
