Advertisements
Advertisements
प्रश्न
Carefully observe the given picture. A mixture of DNA with fragments ranging from 200 base pairs to 2500 base pairs was electrophoresed on agarose gel with the following arrangement.
(a) What result will be obtained on staining with ethidium bromide? Explain with reason.
(b) The above setup was modified and a band with 250 base pairs was obtained at X.
What change(s) were made to the previous design to obtain a band at X? Why did the band appear at position X?
Advertisements
उत्तर
(a) No bands will be obtained as all DNA will be seen in the well only; DNA fragments being negatively charged will not move towards the negative end/cathode. DNA being negatively charged will remain stationed at the positive end/anode end of the agar block.
(b)
- The position of the positive terminal/end/anode and the negative terminal/end/cathode was inter-changed.
- The fragment with the least base pairs will get separated faster and move faster to the anode end.
APPEARS IN
संबंधित प्रश्न
Why is the enzyme cellulase needed for isolating genetic material from plant cells and not form the animal cells?
Mention the difference in the mode of action of exonuclease and endonuclease.
Name the enzymes that are used for the isolation of DNA from bacterial and fungal cells for recombinant DNA technology.
How does restriction endonuclease function?
Answer the following question.
Explain the significance of palindromic nucleotide sequence in the formation of recombinant DNA.
The DNA fragment separated on an agarose gel can be visualized by staining with ______.
Which of the following radioisotope is not suitable for DNA labeling based studies?
In agarose gel electrophoresis, DNA molecules are separated on the basis of their ______.
Would you choose an exonuclease while producing a recombinant DNA molecule?
What does H in’ ‘d’ and ‘III’ refer to in the enzyme Hind III?
