हिंदी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान कक्षा ११

A Force → F = → V × → a → V is the Velocity of the Particle and → a → a is a Constant Vector in the Horizontal Direction. with What Minimum Speed, a Particle of Mass M Be Projected

Advertisements
Advertisements

प्रश्न

A force \[\vec{F} = \vec{v} \times \vec{A}\] is exerted on a particle in addition to the force of gravity, where \[\vec{v}\] is the velocity of the particle and \[\vec{A}\] is a constant vector in the horizontal direction. With what minimum speed, a particle of mass m be projected so that it continues to move without being defelected and with a constant velocity? 

योग
Advertisements

उत्तर

For the particle to move without being deflected and with constant velocity, the net force on the particle should be zero.
\[\vec{F} + m \vec{g} = 0\]
\[\Rightarrow \left( \vec{v} \times \vec{A} \right) + \vec{mg} = 0\]
\[ \Rightarrow \left( \vec{v} \times \vec{A} \right) = - \vec{mg}\]
\[\left| vA\sin\theta \right| = \left| mg \right|\] 
\[\therefore v = \frac{mg}{A\sin\theta}\]
v will be minimum when sinθ = 1.
⇒ θ = 90°
\[\therefore v_{\text{min}} = \frac{mg}{A}\]

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Newton's Laws of Motion - Exercise [पृष्ठ ८०]

APPEARS IN

एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
अध्याय 5 Newton's Laws of Motion
Exercise | Q 21 | पृष्ठ ८०

संबंधित प्रश्न

Two masses 8 kg and 12 kg are connected at the two ends of a light, inextensible string that goes over a frictionless pulley. Find the acceleration of the masses, and the tension in the string when the masses are released.


A spy jumps from an airplane with his parachute. The spy accelerates downward for some time when the parachute opens. The acceleration is suddenly checked and the spy slowly falls to the ground. Explain the action of the parachute in checking the acceleration.


If the tension in the cable supporting an elevator is equal to the weight of the elevator, the elevator may be
(a) going up with increasing speed
(b) going down with increasing speed
(c) going up with uniform speed
(d) going down with uniform speed


 car moving at 40 km/hr is to be stopped by applying brakes in the next 4 m. If the car weighs 2000 kg, what average force must be applied to stop it?


A block of mass 0.2 kg is suspended from the ceiling by a light string. A second block of mass 0.3 kg is suspended from the first block by another string. Find the tensions in the two strings. Take g = 10 m/s2.


A particle of mass 50 g moves in a straight line. The variation of speed with time is shown in the following figure. Find the force acting on the particle at t = 2, 4 and 6 seconds.


Both the springs shown in the following figure are unstretched. If the block is displaced by a distance x and released, what will be the initial acceleration?


In a simple Atwood machine, two unequal masses m1 and m2 are connected by a string going over a clamped light smooth pulley. In a typical arrangement (In the following figure), m1 = 300 g and m2 = 600 g. The system is released from rest. (a) Find the distance travelled by the first block in the first two seconds; (b) find the tension in the string; (c) find the force exerted by the clamp on the pulley.


Find the mass M of the hanging block in the following figure that will prevent the smaller block from slipping over the triangular block. All the surfaces are frictionless and the strings and the pulleys are light.


A block A can slide on a frictionless incline of angle θ and length l, kept inside an elevator going up with uniform velocity v in the following figure. Find the time taken by the block to slide down the length of the incline if it is released from the top of the incline.


An aeroplane is moving uniformly at a constant height under the action of two forces (i) Upward force (lift) and (ii) Downward force (weight). What is the net force on the aeroplane?


Define linear momentum and state its S.I. unit.


Calculate the magnitude of force which when applied on a body of mass 0.5 kg produces an acceleration of 5 m s-2.


ame the law of motion which gives the definition of force.


What do you mean by an impulsive force?


Use Newton's second law to explain the following:
While catching a fast moving ball, we always pull our hands backwards.


In the previous problem (5.3), the magnitude of the momentum transferred during the hit is ______.


The motion of a particle of mass m is given by x = 0 for t < 0 s, x(t) = A sin 4 pt for 0 < t < (1/4) s (A > o), and x = 0 for t > (1/4) s. Which of the following statements is true?

  1. The force at t = (1/8) s on the particle is – 16π2 Am.
  2. The particle is acted upon by on impulse of magnitude 4π2 A m at t = 0 s and t = (1/4) s.
  3. The particle is not acted upon by any force.
  4. The particle is not acted upon by a constant force.
  5. There is no impulse acting on the particle.

How does moving your hand backward while catching a cricket ball reduce pain?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×