HSC Science (Electronics) 12th Standard Board Exam - Maharashtra State Board Question Bank Solutions for Mathematics and Statistics

Solve the following : The position of a particle is given by the function s (t) = 2t² + 3t – 4. Find the time t = c in the interval 0 ≤ t ≤ 4 when the instantaneous velocity of the particle equal to its average velocity in this interval.

Integrate the following w.r.t. x : x³ + x2 – x + 1

Integrate the following w.r.t. x : `int x^2(1 - 2/x)^2 dx`

Integrate the following w.r.t. x:

`3 sec^2x - 4/x + 1/(xsqrt(x)) - 7`

Integrate the following w.r.t. x:

`2x^3 - 5x + 3/x + 4/x^5`

Integrate the following w.r.t. x : `(3x^3 - 2x + 5)/(xsqrt(x)`

Evaluate the following integrals : tan²x dx

Evaluate the following integrals : `int (sin2x)/(cosx)dx`

Evaluate the following integrals : `int sin x/cos^2x dx`

Evaluate the following integrals:

`int (cos2x)/sin^2x dx` 

Evaluate the following integrals : `int (cos2x)/(sin^2x.cos^2x)dx`

Evaluate the following integrals : `int sinx/(1 + sinx)dx`

Evaluate the following integrals : `int tanx/(sec x + tan x)dx`

Evaluate the following integrals : `int sqrt(1 + sin 2x) dx`

Evaluate the following integrals : `intsqrt(1 - cos 2x)dx`

Evaluate the following integrals: `int sin 4x cos 3x dx`

Evaluate the following integrals:

`int x/(x + 2).dx`

Evaluate the following integral: 

`int(4x + 3)/(2x + 1).dx`

Evaluate the following integrals : `int(5x + 2)/(3x - 4).dx`

Evaluate the following integrals: `int(x - 2)/sqrt(x + 5).dx`