English

Integrate the following w.r.t. x : ∫x2(1-2x)2dx

Advertisements
Advertisements

Question

Integrate the following w.r.t. x : `int x^2(1 - 2/x)^2 dx`

Sum
Advertisements

Solution

`int x^2(1 - 2/x)^2 dx`

= `int x^2 (1 - 4/x + 4/x^2)dx`

= `int (x^2 - 4x + 4)dx`

= `intx^2 dx - 4 int x dx + 4 int 1 dx`

= `x^3/(3) - 4(x^2/2) + 4x + c`

= `(1)/(3)x^3 - 2x^2 + 4x + c`.

shaalaa.com
  Is there an error in this question or solution?
Chapter 3: Indefinite Integration - Exercise 3.1 [Page 102]

APPEARS IN

RELATED QUESTIONS

Evaluate : `∫1/(3+2sinx+cosx)dx`


\[\int\sqrt{3 + 2x - x^2} \text{ dx}\]

\[\int\sqrt{4 x^2 - 5}\text{ dx}\]

Write a value of

\[\int\frac{\cos x}{3 + 2 \sin x}\text{  dx}\]

 Write a valoue of \[\int \sin^3 x \cos x\ dx\]

 


Evaluate the following integrals : `int(5x + 2)/(3x - 4).dx`


Evaluate the following integrals : `intsqrt(1 + sin 5x).dx`


Integrate the following functions w.r.t. x : `(logx)^n/x`


Integrate the following functions w.r.t. x : `((sin^-1 x)^(3/2))/(sqrt(1 - x^2)`


Integrate the following functions w.r.t. x : `(1)/(x.logx.log(logx)`.


Integrate the following functions w.r.t. x : sin5x.cos8x


Evaluate the following:

`int (1)/(25 - 9x^2)*dx`


Evaluate the following : `int (1)/(7 + 2x^2).dx`


Evaluate the following : `int sqrt((9 + x)/(9 - x)).dx`


Evaluate the following : `int sqrt((10 + x)/(10 - x)).dx`


Evaluate the following : `int (1)/(1 + x - x^2).dx`


Evaluate the following : `int (1)/sqrt(3x^2 + 5x + 7).dx`


Integrate the following functions w.r.t. x : `int (1)/(3 + 2sin x - cosx)dx`


Integrate the following functions w.r.t. x : `int (1)/(3 + 2 sin2x + 4cos 2x).dx`


Evaluate the following integrals : `int (3x + 4)/(x^2 + 6x + 5).dx`


Evaluate the following integrals : `int (2x + 3)/(2x^2 + 3x - 1).dx`


Evaluate the following integral:

`int (3cosx)/(4sin^2x + 4sinx - 1).dx`


Evaluate the following integrals : `int sqrt((e^(3x) - e^(2x))/(e^x + 1)).dx`


Choose the correct options from the given alternatives :

`int sqrt(cotx)/(sinx*cosx)*dx` =


Choose the correct options from the given alternatives :

`int (e^x(x - 1))/x^2*dx` =


Choose the correct options from the given alternatives :

`int (cos2x - 1)/(cos2x + 1)*dx` =


Fill in the Blank.

`int (5("x"^6 + 1))/("x"^2 + 1)` dx = x4 + ______ x3 + 5x + c


If f '(x) = `1/"x" + "x"` and f(1) = `5/2`, then f(x) = log x + `"x"^2/2` + ______


Evaluate: `int 1/(sqrt("x") + "x")` dx


`int x^2/sqrt(1 - x^6)` dx = ________________


`int 1/(xsin^2(logx))  "d"x`


`int sqrt(x)  sec(x)^(3/2) tan(x)^(3/2)"d"x`


`int x/(x + 2)  "d"x`


Evaluate  `int"e"^x (1/x - 1/x^2)  "d"x`


`int sin^-1 x`dx = ?


`int "e"^(sin^-1 x) ((x + sqrt(1 - x^2))/(sqrt1 - x^2)) "dx" = ?`


If I = `int (sin2x)/(3x + 4cosx)^3 "d"x`, then I is equal to ______.


`int ("d"x)/(x(x^4 + 1))` = ______.


The general solution of the differential equation `(1 + y/x) + ("d"y)/(d"x)` = 0 is ______.


Write `int cotx  dx`.


`int(1 - x)^(-2)` dx = `(1 - x)^(-1) + c`


Evaluate `int1/(x(x - 1))dx`


Evaluate the following.

`int x sqrt(1 + x^2)  dx`


The value of `int ("d"x)/(sqrt(1 - x))` is ______.


Evaluate `int(5x^2-6x+3)/(2x-3) dx`


What is \[\int\cot t\,dt\] in the evaluation of \[\int\frac{\sin x}{\sin(x+a)}\,dx\]?


When applying substitution, what must always be rewritten in terms of the new variable?


For indefinite integrals, what should be done after integration in the new variable?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×