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Maharashtra State BoardSSC (English Medium) 10th Standard

SSC (English Medium) 10th Standard - Maharashtra State Board Question Bank Solutions

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Prove that:

\[\sec\theta + \tan\theta = \frac{\cos\theta}{1 - \sin\theta}\]
[6] Trigonometry
Chapter: [6] Trigonometry
Concept: undefined >> undefined

Prove that:
If \[\tan\theta + \frac{1}{\tan\theta} = 2\], then show that \[\tan^2 \theta + \frac{1}{\tan^2 \theta} = 2\]

[6] Trigonometry
Chapter: [6] Trigonometry
Concept: undefined >> undefined

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Find the point on X-axis which is equidistant from P(2, –5) and Q(–2, 9).

[5] Co-ordinate Geometry
Chapter: [5] Co-ordinate Geometry
Concept: undefined >> undefined

Prove that:

\[\sec^4 A\left( 1 - \sin^4 A \right) - 2 \tan^2 A = 1\]
[6] Trigonometry
Chapter: [6] Trigonometry
Concept: undefined >> undefined

Choose the correct alternative answer for the following question.
sin \[\theta\] cosec \[\theta\]= ?

[6] Trigonometry
Chapter: [6] Trigonometry
Concept: undefined >> undefined

Choose the correct alternative answer for the following question.
cosec 45° =?

[6] Trigonometry
Chapter: [6] Trigonometry
Concept: undefined >> undefined

Choose the correct alternative answer for the following question.

1 + tan2 \[\theta\]  = ?

[6] Trigonometry
Chapter: [6] Trigonometry
Concept: undefined >> undefined

Choose the correct alternative answer for the following question.

When we see at a higher level, from the horizontal line, angle formed is ........
 
[6] Trigonometry
Chapter: [6] Trigonometry
Concept: undefined >> undefined

Prove the following.

secθ (1 – sinθ) (secθ + tanθ) = 1

[6] Trigonometry
Chapter: [6] Trigonometry
Concept: undefined >> undefined

Prove the following.
(secθ + tanθ) (1 – sinθ) = cosθ

[6] Trigonometry
Chapter: [6] Trigonometry
Concept: undefined >> undefined

Prove the following.
sec2θ + cosec2θ = sec2θ × cosec2θ 

[6] Trigonometry
Chapter: [6] Trigonometry
Concept: undefined >> undefined

Prove the following.
cot2θ – tan2θ = cosec2θ – sec2θ

[6] Trigonometry
Chapter: [6] Trigonometry
Concept: undefined >> undefined

Prove the following.

\[\frac{1}{1 - \sin\theta} + \frac{1}{1 + \sin\theta} = 2 \sec^2 \theta\]
[6] Trigonometry
Chapter: [6] Trigonometry
Concept: undefined >> undefined

Prove the following:

sec6x – tan6x = 1 + 3sec2x × tan2x

[6] Trigonometry
Chapter: [6] Trigonometry
Concept: undefined >> undefined

Prove the following.

\[\frac{\tan\theta}{\sec\theta + 1} = \frac{\sec\theta - 1}{\tan\theta}\]

[6] Trigonometry
Chapter: [6] Trigonometry
Concept: undefined >> undefined

Prove the following.

\[\frac{\tan^3 \theta - 1}{\tan\theta - 1} = \sec^2 \theta + \tan\theta\]
[6] Trigonometry
Chapter: [6] Trigonometry
Concept: undefined >> undefined

In the adjoining figure, point O is the centre of the cirlcle, seg OM ⊥ chord AB. If OM = 8cm, AB = 12 cm, then find OB.

[3] Circle
Chapter: [3] Circle
Concept: undefined >> undefined

In ∆PQR, PQ = √8 , QR = √5 , PR = √3. Is ∆PQR a right-angled triangle? If yes, which angle is of 90°?

[2] Pythagoras Theorem
Chapter: [2] Pythagoras Theorem
Concept: undefined >> undefined

Sides of the triangle are 7 cm, 24 cm, and 25 cm. Determine whether the triangle is a right-angled triangle or not. 

[2] Pythagoras Theorem
Chapter: [2] Pythagoras Theorem
Concept: undefined >> undefined

Choose the correct alternative: 
sinθ × cosecθ =?

[6] Trigonometry
Chapter: [6] Trigonometry
Concept: undefined >> undefined
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Maharashtra State Board SSC (English Medium) 10th Standard Question Bank Solutions
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Question Bank Solutions for Maharashtra State Board SSC (English Medium) 10th Standard Marathi (Second Language) [मराठी (द्वितीय भाषा)]
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