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(English Medium) ICSE Class 10 - CISCE Question Bank Solutions

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Find the values of k so that the sum of tire roots of the quadratic equation is equal to the product of the roots in each of the following:
kx2 + 2x + 3k = 0

[5] Quadratic Equations
Chapter: [5] Quadratic Equations
Concept: undefined >> undefined

Find the values of k so that the sum of tire roots of the quadratic equation is equal to the product of the roots in each of the following:
2x2 - (3k + 1)x - k + 7 = 0.

[5] Quadratic Equations
Chapter: [5] Quadratic Equations
Concept: undefined >> undefined

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Given that one root of the quadratic equation ax2 + bx + c = 0 is three times the other, show that 3b2 – 16ac.

[5] Quadratic Equations
Chapter: [5] Quadratic Equations
Concept: undefined >> undefined

If one root of the quadratic equation ax2 + bx + c = 0 is double the other, prove that 2b2 = 9 ac.

[5] Quadratic Equations
Chapter: [5] Quadratic Equations
Concept: undefined >> undefined

If the ratio of the roots of the equation
lx2 + nx + n = 0 is p: q, Prove that
`sqrt(p/q) + sqrt(q/p) + sqrt(n/l) = 0.`

[5] Quadratic Equations
Chapter: [5] Quadratic Equations
Concept: undefined >> undefined

Find the value of a and b so that the polynomial x3 - ax2 - 13x + b has (x - 1) (x + 3) as factor.

[7] Factorisation of Polynomials
Chapter: [7] Factorisation of Polynomials
Concept: undefined >> undefined

If the polynomials ax3 + 4x2 + 3x - 4 and x3 - 4x + a leave the same remainder when divided by (x - 3), find the value of a.

[7] Factorisation of Polynomials
Chapter: [7] Factorisation of Polynomials
Concept: undefined >> undefined

In the following two polynomials. Find the value of ‘a’ if x + a is a factor of each of the two:

x3 + ax2 − 2x + a + 4

[7] Factorisation of Polynomials
Chapter: [7] Factorisation of Polynomials
Concept: undefined >> undefined

In the following two polynomials. Find the value of ‘a’ if x + a is a factor of each of the two:
x4 - a2x2 + 3x - a.

[7] Factorisation of Polynomials
Chapter: [7] Factorisation of Polynomials
Concept: undefined >> undefined

In the following two polynomials, find the value of ‘a’ if x – a is a factor of each of the two:
x6 - ax5 + x4 - ax3 + 3a + 2

[7] Factorisation of Polynomials
Chapter: [7] Factorisation of Polynomials
Concept: undefined >> undefined

In the following two polynomials, find the value of ‘a’ if x – a is a factor of each of the two:
x5 - a2x3 + 2x + a + 1.

[7] Factorisation of Polynomials
Chapter: [7] Factorisation of Polynomials
Concept: undefined >> undefined

If x – 2 is a factor of each of the following three polynomials. Find the value of ‘a’ in each case:
x2 - 3x + 5a

[7] Factorisation of Polynomials
Chapter: [7] Factorisation of Polynomials
Concept: undefined >> undefined

If x – 2 is a factor of each of the following three polynomials. Find the value of ‘a’ in each case:
x3 + 2ax2 + ax - 1

[7] Factorisation of Polynomials
Chapter: [7] Factorisation of Polynomials
Concept: undefined >> undefined

If x – 2 is a factor of each of the following three polynomials. Find the value of ‘a’ in each case:
x5 - 3x4 - ax3 + 3ax2 + 2ax + 4.

[7] Factorisation of Polynomials
Chapter: [7] Factorisation of Polynomials
Concept: undefined >> undefined

In the given figure, O is the centre of the circle and ∠PBA = 45°. Calculate the value of ∠PQB.

[13] Circles
Chapter: [13] Circles
Concept: undefined >> undefined

Show that x2 - 9 is factor of x3 + 5x2 - 9x - 45.

[7] Factorisation of Polynomials
Chapter: [7] Factorisation of Polynomials
Concept: undefined >> undefined

In the given figure, BAD = 65°, ABD = 70°, BDC = 45°.
(i) Prove that AC is a diameter of the circle.
(ii) Find ACB.

[13] Circles
Chapter: [13] Circles
Concept: undefined >> undefined

In Fig, Chord ED is parallel to the diameter AC of the circle. Given ∠CBE = 65°, Calculate ∠ DEC.

[13] Circles
Chapter: [13] Circles
Concept: undefined >> undefined

In the figure, ∠DBC = 58°. BD is diameter of the circle.

Calculate:

  1. ∠BDC
  2. ∠BEC
  3. ∠BAC

[13] Circles
Chapter: [13] Circles
Concept: undefined >> undefined

In the figure given alongside, AD is the diameter of the circle. If ∠ BCD = 130°, Calculate: (i) ∠ DAB (ii) ∠ ADB.

[13] Circles
Chapter: [13] Circles
Concept: undefined >> undefined
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