English Medium Class 9 - CBSE Question Bank Solutions

The value of \[\sqrt{5 + 2\sqrt{6}}\] is

If \[\sqrt{2} = 1 . 4142\] then \[\sqrt{\frac{\sqrt{2} - 1}{\sqrt{2} + 1}}\] is equal to

If \[\sqrt{2} = 1 . 414,\] then the value of \[\sqrt{6} - \sqrt{3}\] upto three places of decimal is

The positive square root of \[7 + \sqrt{48}\] is 

If \[x = \sqrt{6} + \sqrt{5}\],then \[x^2 + \frac{1}{x^2} - 2 =\]

If \[\sqrt{13 - a\sqrt{10}} = \sqrt{8} + \sqrt{5}, \text { then a } =\]

If \[x - \frac{1}{x} = - 1\]  find the value of  \[x^2 + \frac{1}{x^2}\]

Find the cube of the following binomials expression :

\[\frac{1}{x} + \frac{y}{3}\]

Find the cube of the following binomials expression :

\[\frac{3}{x} - \frac{2}{x^2}\]

Find the cube of the following binomials expression :

\[2x + \frac{3}{x}\]

Find the cube of the following binomials expression :

\[4 - \frac{1}{3x}\]

If a − b = 4 and ab = 21, find the value of a³ −b³

If \[x + \frac{1}{x} = 5\], find the value of \[x^3 + \frac{1}{x^3}\]

If \[x - \frac{1}{x} = 7\], find the value of \[x^3 - \frac{1}{x^3}\].

If \[x - \frac{1}{x} = 5\], find the value of \[x^3 - \frac{1}{x^3}\]

If  \[x^2 + \frac{1}{x^2}\], find the value of \[x^3 - \frac{1}{x^3}\]

If \[x^2 + \frac{1}{x^2} = 98\] ,find the value of \[x^3 + \frac{1}{x^3}\]