Secondary School (English Medium) (5 to 8) Class 8 - CBSE Question Bank Solutions

[2^–1 + 3^–1 + 4^–1]⁰ = ______.

By multiplying `(5/3)^4` by ______ we get 5⁴.

3⁵ ÷ 3^–6 can be simplified as ______.

On dividing 8⁵ by ______ we get 8.

On multiplying ______ by 2^–5 we get 2⁵.

On multiplying ______ by 2^–5 we get 2⁵.

The value of [3^–1 × 4^–1]² is ______.

The value of [2^–1 × 3^–1]^–1 is ______.

By solving (6⁰ – 7⁰) × (6⁰ + 7⁰) we get ______.

The expression for 3⁵ with a negative exponent is ______.

The value for (–7)⁶ ÷ 7⁶ is ______.

The value of [1^–2 + 2^–2 + 3^–2 ] × 6² is ______.

`10^-2 = 1/100`

329.25 = 3 × 10² + 2 × 10¹ + 9 × 10⁰ + 2 × 10^–1 + 5 × 10^–2 

(–5)^–2 × (–5)^–3 = (–5)^–6 

(–4)^–4 × (4)^–1 = (4)⁵  

`(2/3)^-2 xx (2/3)^-5 = (2/3)^10`

5⁰ = 5

(–2)⁰ = 2

`(-8/2)^0 = 0`