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Question
[2–1 + 3–1 + 4–1]0 = ______.
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Solution
[2–1 + 3–1 + 4–1]0 = 1.
Explanation:
Using law of exponents,
a0 = 1 ...[∵ a is non-zero integer]
∴ [2–1 + 3–1 + 4–1]0 = 1
Hence, [2–1 + 3–1 + 4–1]0 = 1
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