Advertisements
Advertisements
Question
In a repeater machine with 0 as an exponent, the base machine is applied 0 times. What do these machines do to a piece of chalk?

Advertisements
Solution
Since, 30 = 1, 130 = 1, 290 = 1
Using law of exponents,
a0 = 1 ...[∵ a is non-zero integer]
So, machine (× 30), (× 130) and (× 290) produce nothing on not change the piece 7 chalk.
APPEARS IN
RELATED QUESTIONS
`((-7)/5)^-1` is equal to ______.
For a non-zero rational number z, (z–2)3 is equal to ______.
50 = ______.
(–7)–4 × (–7)2 = (–7)–2
`x^m/y^m = (y/x)^-m`
Express as a power of a rational number with negative exponent.
`(((-3)/2)^-2)^-3`
Find a single machine that will do the same job as the given hook-up.
a (× 24) machine followed by `(xx (1/2)^2)` machine.
Find a single repeater machine that will do the same work as hook-up.

For hook-up, determine whether there is a single repeater machine that will do the same work. If so, describe or draw it.

Simplify:
`[(4/3)^-2 - (3/4)^2]^((-2))`
