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Question
What happens when 1 cm worms are sent through these hook-ups?
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Solution
If 1 cm worms are sent through (× 2–1) and (× 2)–2 hooked machine, the result comes with `1 xx 1/2 xx 1/(2 xx 2)`
= `1/(2 xx 4)`
= `1/8`
= 0.125 cm
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An insect is on the 0 point of a number line, hopping towards 1. She covers half the distance from her current location to 1 with each hop. So, she will be at `1/2` after one hop, `3/4` after two hops, and so on.
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| Input Length | Repeater Machine | ||
| × 23 | |||
| 40 | 125 | ||
| 2 | |||
| 162 | |||
Simplify:
`[(4/3)^-2 - (3/4)^2]^((-2))`
