Advertisements
Advertisements
Question
By solving (60 – 70) × (60 + 70) we get ______.
Fill in the Blanks
Advertisements
Solution
By solving (60 – 70) × (60 + 70) we get 0.
Explanation:
Using law of exponents,
a0 = 1 ...[∵ a is non-zero integer]
∴ (60 – 70) × (60 + 70) = (1 – 1) × (1 + 1)
= 0 × 2
= 0
Hence, (60 – 70) × (60 + 70) = 0
shaalaa.com
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
The reciprocal of `(2/5)^-1` is ______.
If x be any non-zero integer, then x–1 is equal to ______.
For a non-zero integer x, (x4)–3 is equal to ______.
`(1/10)^0` is equal to ______.
55 × 5–5 = ______.
`[(2/13)^-6 ÷ (2/13)^3]^3 xx (2/13)^-9` = ______.
`(2/3)^-2 xx (2/3)^-5 = (2/3)^10`
ap × bq = (ab)pq
Find a single repeater machine that will do the same work as hook-up.
Supply the missing information for diagram.
