Advertisements
Advertisements
प्रश्न
By solving (60 – 70) × (60 + 70) we get ______.
Advertisements
उत्तर
By solving (60 – 70) × (60 + 70) we get 0.
Explanation:
Using law of exponents,
a0 = 1 ...[∵ a is non-zero integer]
∴ (60 – 70) × (60 + 70) = (1 – 1) × (1 + 1)
= 0 × 2
= 0
Hence, (60 – 70) × (60 + 70) = 0
APPEARS IN
संबंधित प्रश्न
50 = ______.
Simplify:
`(49 xx z^-3)/(7^-3 xx 10 xx z^-5) (z ≠ 0)`
Simplify:
(25 ÷ 28) × 2–7
If `(5^m xx 5^3 xx 5^-2)/5^-5 = 5^12`, find m.
Find a single repeater machine that will do the same work as hook-up.
Find a single repeater machine that will do the same work as hook-up.
For hook-up, determine whether there is a single repeater machine that will do the same work. If so, describe or draw it.
The diameter of the Sun is 1.4 × 109 m and the diameter of the Earth is 1.2756 × 107 m. Compare their diameters by division.
If a = – 1, b = 2, then find the value of the following:
ab ÷ ba
Simplify:
`[(1/2)^2 - (1/4)^3]^-1 xx 2^-3`
