Advertisements
Advertisements
प्रश्न
Consider a quantity of a radioactive substance. The fraction of this quantity that remains after t half-lives can be found by using the expression 3–t. What fraction of substance remains after 7 half-lives?
Advertisements
उत्तर
Since, 3–t expression is used for finding the fraction of the quality that remains after t half-lives.
Hence, the fraction of substance remains after 7 half-lives will be equal to 3–7 i.e., `1/3^7`.
APPEARS IN
संबंधित प्रश्न
The value of 35 ÷ 3–6 is ______.
If x be any non-zero integer and m, n be negative integers, then xm × xn is equal to ______.
The value for (–7)6 ÷ 76 is ______.
The expontential form for `(-2)^4 xx (5/2)^4` is 54.
The value of 5–2 is equal to 25.
Express as a power of a rational number with negative exponent.
(25 ÷ 28) × 2–7
Find the value of x so that (–2)3 × (–2)–6 = (–2)2x – 1
Find the multiplicative inverse of (–7)–2 ÷ (90)–1.
By what number should `((-3)/2)^-3` be divided so that the quotient may be `(4/27)^-2`?
If possible, find a hook-up of prime base number machine that will do the same work as the given stretching machine. Do not use (× 1) machines.
