Advertisements
Advertisements
प्रश्न
By what number should `((-3)/2)^-3` be divided so that the quotient may be `(4/27)^-2`?
Advertisements
उत्तर
Let `((-3)/2)^-3` be divided by x to get `(4/27)^-2` as quotient.
Then, `((-3)/2)^-3 ÷ x = (4/27)^-2`
⇒ `x = ((-3)/2)^-3 ÷ (2^2/3^3)^-2 = ((-3)/2)^-3 ÷ (2)^-4/(3)^-6`
= `((-3)/2)^-3 xx (3)^-6/(2)^-4`
= `((-3)^-3 xx (3)^-6)/(2^-3 xx 2^-4` ...[∵ am × an = am + n]
= `3^-9/2^-7`
= `2^7/3^9` ...`[∵ a^-m = 1/a^m "and" (a^m)^n = (a)^(mn)]`
APPEARS IN
संबंधित प्रश्न
Simplify and write the answer in the exponential form.
`(3/4)^5 ÷ (5/3)^5` is equal to ______.
By multiplying (10)5 by (10)–10 we get ______.
35 ÷ 3–6 can be simplified as ______.
329.25 = 3 × 102 + 2 × 101 + 9 × 100 + 2 × 10–1 + 5 × 10–2
(–4)–4 × (4)–1 = (4)5
`(-8/2)^0 = 0`
Find the value of x so that `(5/3)^-2 xx (5/3)^-14 = (5/3)^(8x)`
An insect is on the 0 point of a number line, hopping towards 1. She covers half the distance from her current location to 1 with each hop. So, she will be at `1/2` after one hop, `3/4` after two hops, and so on.

- Make a table showing the insect’s location for the first 10 hops.
- Where will the insect be after n hops?
- Will the insect ever get to 1? Explain.
In a repeater machine with 0 as an exponent, the base machine is applied 0 times. What do these machines do to a piece of chalk?

