Advertisements
Advertisements
प्रश्न
By what number should `((-3)/2)^-3` be divided so that the quotient may be `(4/27)^-2`?
Advertisements
उत्तर
Let `((-3)/2)^-3` be divided by x to get `(4/27)^-2` as quotient.
Then, `((-3)/2)^-3 ÷ x = (4/27)^-2`
⇒ `x = ((-3)/2)^-3 ÷ (2^2/3^3)^-2 = ((-3)/2)^-3 ÷ (2)^-4/(3)^-6`
= `((-3)/2)^-3 xx (3)^-6/(2)^-4`
= `((-3)^-3 xx (3)^-6)/(2^-3 xx 2^-4` ...[∵ am × an = am + n]
= `3^-9/2^-7`
= `2^7/3^9` ...`[∵ a^-m = 1/a^m "and" (a^m)^n = (a)^(mn)]`
APPEARS IN
संबंधित प्रश्न
For a non-zero integer x, x7 ÷ x12 is equal to ______.
`10^-2 = 1/100`
329.25 = 3 × 102 + 2 × 101 + 9 × 100 + 2 × 10–1 + 5 × 10–2
(–2)0 = 2
The value of 5–2 is equal to 25.
A new born bear weighs 4 kg. How many kilograms might a five year old bear weigh if its weight increases by the power of 2 in 5 years?
The cells of a bacteria double in every 30 minutes. A scientist begins with a single cell. How many cells will be there after 24 hours?
Planet A is at a distance of 9.35 × 106 km from Earth and planet B is 6.27 × 107 km from Earth. Which planet is nearer to Earth?
An insect is on the 0 point of a number line, hopping towards 1. She covers half the distance from her current location to 1 with each hop. So, she will be at `1/2` after one hop, `3/4` after two hops, and so on.
Will the insect ever get to 1? Explain.
Simplify:
`((3^-2)^2 xx (5^2)^-3 xx (t^-3)^2)/((3^-2)^5 xx (5^3)^-2 xx (t^-4)^3`
