Advertisements
Advertisements
Question
Consider a quantity of a radioactive substance. The fraction of this quantity that remains after t half-lives can be found by using the expression 3–t. What fraction of substance remains after 7 half-lives?
Advertisements
Solution
Since, 3–t expression is used for finding the fraction of the quality that remains after t half-lives.
Hence, the fraction of substance remains after 7 half-lives will be equal to 3–7 i.e., `1/3^7`.
APPEARS IN
RELATED QUESTIONS
For a non-zero rational number p, p13 ÷ p8 is equal to ______.
The value of `(1/2^3)^2` is equal to ______.
50 = 5
(–2)0 = 2
(–7)–4 × (–7)2 = (–7)–2
The expontential form for `(-2)^4 xx (5/2)^4` is 54.
Simplify:
`(1/4)^-2 + (1/2)^-2 + (1/3)^-2`
What happens when 1 cm worms are sent through these hook-ups?
Find a single repeater machine that will do the same work as hook-up.
Supply the missing information for diagram.
