Advertisements
Advertisements
प्रश्न
In a repeater machine with 0 as an exponent, the base machine is applied 0 times. What do these machines do to a piece of chalk?

Advertisements
उत्तर
Since, 30 = 1, 130 = 1, 290 = 1
Using law of exponents,
a0 = 1 ...[∵ a is non-zero integer]
So, machine (× 30), (× 130) and (× 290) produce nothing on not change the piece 7 chalk.
APPEARS IN
संबंधित प्रश्न
Simplify and write the answer in the exponential form.
`(- 3)^4 xx (5/3)^4`
The value of `(2/5)^-2` is ______.
The value of (–2)2×3 – 1 is ______.
For a non-zero rational number p, p13 ÷ p8 is equal to ______.
35 ÷ 3–6 can be simplified as ______.
The value of [3–1 × 4–1]2 is ______.
Solve the following:
2–2 × 2–3
Find the value of x so that `(5/3)^-2 xx (5/3)^-14 = (5/3)^(8x)`
Find a single machine that will do the same job as the given hook-up.
a (× 599) machine followed by a (5–100) machine.
If a = – 1, b = 2, then find the value of the following:
ab ÷ ba
