Advertisements
Advertisements
प्रश्न
In a repeater machine with 0 as an exponent, the base machine is applied 0 times. What do these machines do to a piece of chalk?

Advertisements
उत्तर
Since, 30 = 1, 130 = 1, 290 = 1
Using law of exponents,
a0 = 1 ...[∵ a is non-zero integer]
So, machine (× 30), (× 130) and (× 290) produce nothing on not change the piece 7 chalk.
APPEARS IN
संबंधित प्रश्न
Simplify and write the answer in the exponential form.
(25 ÷ 28)5 × 2-5
The reciprocal of `(2/5)^-1` is ______.
The value of `(1/2^3)^2` is equal to ______.
The expontential form for `(-2)^4 xx (5/2)^4` is 54.
`(125 xx x^-3)/(5^-3 xx 25 xx x^-6)`
Find a single repeater machine that will do the same work as hook-up.

For hook-up, determine whether there is a single repeater machine that will do the same work. If so, describe or draw it.

Find x.
`(2/5)^(2x + 6) xx (2/5)^3 = (2/5)^(x + 2)`
Find x.
23x = 82x + 1
If a = – 1, b = 2, then find the value of the following:
ab – ba
