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Arts (English Medium) Class 11 - CBSE Question Bank Solutions for Mathematics

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Write the following relations as sets of ordered pairs and find which of them are functions:

{(xy) : x + y = 3, xy, ∈ [0, 1, 2, 3]}

 

 

[2] Relations and Functions
Chapter: [2] Relations and Functions
Concept: undefined >> undefined

Express the function f : X → given by f(x) = x+ 1 as set of ordered pairs, where X = {−1, 0, 3, 9, 7}

[2] Relations and Functions
Chapter: [2] Relations and Functions
Concept: undefined >> undefined

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Find the 11th term from the beginning and the 11th term from the end in the expansion of  \[\left( 2x - \frac{1}{x^2} \right)^{25}\] .

 

[7] Binomial Theorem
Chapter: [7] Binomial Theorem
Concept: undefined >> undefined

Find the 7th term in the expansion of \[\left( 3 x^2 - \frac{1}{x^3} \right)^{10}\] .

 
[7] Binomial Theorem
Chapter: [7] Binomial Theorem
Concept: undefined >> undefined

Find the 5th term from the end in the expansion of \[\left( 3x - \frac{1}{x^2} \right)^{10}\]

 
[7] Binomial Theorem
Chapter: [7] Binomial Theorem
Concept: undefined >> undefined

Find the 8th term in the expansion of  \[\left( x^{3/2} y^{1/2} - x^{1/2} y^{3/2} \right)^{10}\]

  
[7] Binomial Theorem
Chapter: [7] Binomial Theorem
Concept: undefined >> undefined

Find the 7th term in the expansion of \[\left( \frac{4x}{5} + \frac{5}{2x} \right)^8\]

 
[7] Binomial Theorem
Chapter: [7] Binomial Theorem
Concept: undefined >> undefined

Find the 4th term from the beginning and 4th term from the end in the expansion of \[\left( x + \frac{2}{x} \right)^9\] .

 
[7] Binomial Theorem
Chapter: [7] Binomial Theorem
Concept: undefined >> undefined

Find the 4th term from the end in the expansion of \[\left( \frac{4x}{5} - \frac{5}{2x} \right)^8\] .

 
[7] Binomial Theorem
Chapter: [7] Binomial Theorem
Concept: undefined >> undefined

Find the 7th term from the end in the expansion of \[\left( 2 x^2 - \frac{3}{2x} \right)^8\] .

 
[7] Binomial Theorem
Chapter: [7] Binomial Theorem
Concept: undefined >> undefined

Find the sixth term in the expansion  \[\left( y^\frac{1}{2} + x^\frac{1}{3} \right)^n\] , if the binomial coefficient of the third term from the end is 45.

 
 
[7] Binomial Theorem
Chapter: [7] Binomial Theorem
Concept: undefined >> undefined

Find n in the binomial \[\left( \sqrt[3]{2} + \frac{1}{\sqrt[3]{3}} \right)^n\] , if the ratio of 7th term from the beginning to the 7th term from the end is  \[\frac{1}{6}\]

 
 
[7] Binomial Theorem
Chapter: [7] Binomial Theorem
Concept: undefined >> undefined

if the seventh term from the beginning and end in the binomial expansion of  \[\left( \sqrt[3]{2} + \frac{1}{\sqrt[3]{3}} \right)^n\] are equal, find n.

 
 
[7] Binomial Theorem
Chapter: [7] Binomial Theorem
Concept: undefined >> undefined

Write the number of terms in the expansion of \[\left( 2 + \sqrt{3}x \right)^{10} + \left( 2 - \sqrt{3}x \right)^{10}\] . 

[7] Binomial Theorem
Chapter: [7] Binomial Theorem
Concept: undefined >> undefined

Write the number of terms in the expansion of \[\left( 2 + \sqrt{3}x \right)^{10} + \left( 2 - \sqrt{3}x \right)^{10}\] . 

[7] Binomial Theorem
Chapter: [7] Binomial Theorem
Concept: undefined >> undefined

Write the number of terms in the expansion of \[\left( 1 - 3x + 3 x^2 - x^3 \right)^8\]

 
[7] Binomial Theorem
Chapter: [7] Binomial Theorem
Concept: undefined >> undefined

Which term is independent of x, in the expansion of \[\left( x - \frac{1}{3 x^2} \right)^9 ?\]

 
[7] Binomial Theorem
Chapter: [7] Binomial Theorem
Concept: undefined >> undefined

Write the number of terms in the expansion of  \[\left[ \left( 2x + y^3 \right)^4 \right]^7\] .

 
[7] Binomial Theorem
Chapter: [7] Binomial Theorem
Concept: undefined >> undefined

Find the number of terms in the expansion of\[\left( a + b + c \right)^n\]

 
[7] Binomial Theorem
Chapter: [7] Binomial Theorem
Concept: undefined >> undefined

If rth term in the expansion of \[\left( 2 x^2 - \frac{1}{x} \right)^{12}\]  is without x, then r is equal to

 
[7] Binomial Theorem
Chapter: [7] Binomial Theorem
Concept: undefined >> undefined
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