English Medium Class 10 - CBSE Question Bank Solutions for Mathematics

\[\frac{\sin \theta}{1 + \cos \theta}\]is equal to 

\[\frac{1 - \sin \theta}{\cos \theta}\] is equal to

The value of (1 + cot θ − cosec θ) (1 + tan θ + sec θ) is 

\[\frac{\tan \theta}{\sec \theta - 1} + \frac{\tan \theta}{\sec \theta + 1}\] is equal to 

(cosec θ − sin θ) (sec θ − cos θ) (tan θ + cot θ) is equal to

If x = a cos θ and y = b sin θ, then b²x² + a²y² =

If x = a sec θ and y = b tan θ, then b²x² − a²y² =

\[\frac{\tan \theta}{\sec \theta - 1} + \frac{\tan \theta}{\sec \theta + 1}\] is equal to 

2 (sin⁶ θ + cos⁶ θ) − 3 (sin⁴ θ + cos⁴ θ) is equal to 

If a cos θ + b sin θ = 4 and a sin θ − b sin θ = 3, then a² + b² = 

If a cot θ + b cosec θ = p and b cot θ − a cosec θ = q, then p² − q² 

The value of sin² 29° + sin² 61° is

If x = r sin θ cos ϕ, y = r sin θ sin ϕ and z = r cos θ, then 

If sin θ + sin² θ = 1, then cos² θ + cos⁴ θ = 

If a cos θ + b sin θ = m and a sin θ − b cos θ = n, then a² + b² =

If cos A + cos² A = 1, then sin² A + sin⁴ A =

If x = a sec θ cos ϕ, y = b sec θ sin ϕ and z = c tan θ, then\[\frac{x^2}{a^2} + \frac{y^2}{b^2}\]

If a cos θ − b sin θ = c, then a sin θ + b cos θ =

9 sec² A − 9 tan² A is equal to

(sec A + tan A) (1 − sin A) = ______.