English Medium Class 10 - CBSE Question Bank Solutions for Mathematics

`sin^2 theta + 1/((1+tan^2 theta))=1`

`1/((1+tan^2 theta)) + 1/((1+ tan^2 theta))`

`(1+ cos theta)(1- costheta )(1+cos^2 theta)=1`

`cosec theta (1+costheta)(cosectheta - cot theta )=1`

`cot^2 theta - 1/(sin^2 theta ) = -1`a

` tan^2 theta - 1/( cos^2 theta )=-1`

`cos^2 theta + 1/((1+ cot^2 theta )) =1`

`1/((1+ sin θ)) + 1/((1 - sin θ)) = 2 sec^2 θ`

`sec theta (1- sin theta )( sec theta + tan theta )=1`

`sin theta (1+ tan theta) + cos theta (1+ cot theta) = ( sectheta+ cosec  theta)`

`1+ (cot^2 theta)/((1+ cosec theta))= cosec theta`

`1+(tan^2 theta)/((1+ sec theta))= sec theta`

`1+((tan^2 theta) cot theta)/(cosec^2 theta) = tan theta`

`(tan^2theta)/((1+ tan^2 theta))+ cot^2 theta/((1+ cot^2 theta))=1`

`sin theta / ((1+costheta))+((1+costheta))/sin theta=2cosectheta` 

`tan theta /((1 - cot theta )) + cot theta /((1 - tan theta)) = (1+ sec theta cosec  theta)`

`cos^2 theta /((1 tan theta))+ sin ^3 theta/((sin theta - cos theta))=(1+sin theta cos theta)`

`costheta/((1-tan theta))+sin^2theta/((cos theta-sintheta))=(cos theta+ sin theta)`

`(1+tan^2theta)(1+cot^2 theta)=1/((sin^2 theta- sin^4theta))`

`tan theta/(1+ tan^2 theta)^2 + cottheta/(1+ cot^2 theta)^2 = sin theta cos theta`