Question

`1+((tan^2 theta) cot theta)/(cosec^2 theta) = tan theta`

Answer 1

LHS = `((1+ tan^2 theta) cot theta)/ (cosec^2 theta) `

       = ` (sec^2 theta cot theta)/(cosec^2 theta )`

       = `(1/cos^2thetaxxcos theta/sin theta)/(1/sin^2 theta)`

       = `1/(cos theta sin theta) xx sin^2 theta`

        = `sintheta/costheta`

         = ` tan theta`

          = RHS 

         Hence, LHS = RHS