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Z1 = 1 + i, z2 = 2 − 3i. Verify the following : (z1z2)¯=z1¯z2¯ - Mathematics and Statistics

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Question

z1 = 1 + i, z2 = 2 − 3i. Verify the following :

`bar(("z"_1/"z"_2))=bar("z"_1)/bar("z"_2)`

Sum
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Solution

z1 = 1 + i and z2 = 2 − 3i

∴ `bar("z"_1)` = 1 − i and `bar("z"_2)` = 2 + 3i

`"z"_1/"z"_2 = (1 + "i")/(2 -3"i")` 

= `(1 + "i")/(2 - 3"i") xx (2 + 3"i")/(2 + 3"i")`

= `(2 + 3"i" + 2"i" + 3"i"^2)/(4 - 9"i"^2)`

=`(2 + 5"i" - 3)/(4 + 9)`    ...[∵ i2 = – 1]

=`(-1 + 5"i")/13`

=`-1/13 + 5/13"i"` 

∴ `bar(("z"_1/"z"_2)) = -1/13 - 5/13"i"` .......(1)

`bar("z"_1)/(bar("z")_2) = (1 - "i")/(2 + 3"i")`

= `(1 - "i")/(2 + 3"i") xx (2 - 3"i")/(2 - 3"i")`

= `(2- 3"i" - 2"i" + 3"i"^2)/(4 - 9"i"^2)`

= `(2 - 5"i" - 3)/(4 + 9)`   ...[∵ i2 = – 1]

= `(-1 - 5"i")/13`

= `-1/13 - 5/13"i"` ........(2)

From (1) and (2), we get,

`bar(("z"_1/"z"_2))=bar("z"_1)/bar("z"_2)`

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Chapter 1: Complex Numbers - Exercise 1.3 [Page 15]

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