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Question
z1 = 1 + i, z2 = 2 − 3i. Verify the following :
`bar("z"_1 + "z"_2) = bar("z"_1) + bar("z"_2)`
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Solution
z1 = 1 + i, z2 = 2 − 3i
∴ `bar("z"_1)` = 1 − i, `bar("z"_2)` = 2 + 3i
z1 + z2 = (1 + i) + (2 − 3i) = 3 − 2i
∴ `bar("z"_1 + "z"_2)` = 3 + 2i
`bar("z"_1) + bar("z"_2)` = (1 − i) + (2 + 3i)
= 3 + 2i
∴ `bar("z"_1 + "z"_2) = bar("z"_1) + bar("z"_2)`
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